x=x^2-2x+3

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Solution for x=x^2-2x+3 equation: 



x=x^2-2x+3

We move all terms to the left:

x-(x^2-2x+3)=0

We get rid of parentheses

-x^2+x+2x-3=0

We add all the numbers together, and all the variables

-1x^2+3x-3=0

a = -1; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-1)·(-3)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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